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vladimir2022 [97]

2 years ago

5

Will mark brainlist! Andrea spent $2 to make 10 prints from a photo both. Later, she spent $6 to make 30 prints. Did she get a b

etter deal the first or second time she purchased prints. How do you know?

1 answer:

notka56 [123]2 years ago

3 0

Answer:

She got an equally good deal both times

Step-by-step explanation:

$\frac{2}{20}$ can be simplified to make $\frac{1}{5}$

$\frac{6}{30}$ can be simplified to make $\frac{1}{5}$

they are the same

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Write the following numbers in order, putting the largest

fiasKO [112]

Answer:

a)

31.53

31.099

31.009 ⬅ (I'm assuming this one is a decimal too)

b)

0.03

0.009

0.007

Explanation:

Here ya go.

Hope this helps :)

5 0

2 years ago

Please help me with these I’m so confused (best answer = Brainliest)

lana66690 [7]

For the box plot, plot the minimum and maximum on a line. then find the median of the data. divide the data into two groups and find the median of each and graph those, then draw the boxes. IQR is the third quartile minus the first. a quartile is a quartile regardless of size. both boxes are quartiles and both tails are too. hope that makes sense

6 0

3 years ago

Annual sales for a company are $155,000 and increases at a rate if 8% per year for 9 years

Zepler [3.9K]

Answer:

number 5

hope this helps you !!

8 0

2 years ago

Read 2 more answers

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

2 years ago

Find the value of x 11x-15 and 5x-13

Vinvika [58]

11x -15 = 5x-13

or, 11x-5x = -13+15

or, 6x = 2

or, x = 2/6 = 1/3

Answer is 1/3

7 0

2 years ago