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3 years ago

53

Mathematics

1 answer:

jolli1 [7]3 years ago

7 0

Is this shape a triangle????

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What do I need to do for the second question???

borishaifa [10]

You need to take the data, and you need to have his income recorded as a rise early on. Then you need to peak the data at an early-mid point and then demonstrate that his income is decreasing steadily.

8 0

4 years ago

Will someone please help me? I will give brainliest

zavuch27 [327]

Answer:

A, E

Step-by-step explanation:

We can use rules of fractions and negatives to determine that B, C, and D are incorrect and A and E are correct.

4 0

3 years ago

Maggie is planning on going to Penn State University. She estimates that she will need to earn at least $2,000 to live off of ov

professor190 [17]

A. The amount of money she must earn in the summer must be
x ≥ 2450

B. The inequality that describes the situation is
30x ≤ 2000

C. Solving the inequality
x ≤ 66.67 ~ 66 weeks

D. The answer is Part C means that she can only make use of the $2000 money for food for 66 weeks before it's not enough.

8 0

3 years ago

An investor buys Rs.1200 worth of share in company first 5 monnths he bought the share at price of Rs.10,12,15,20 and 24 per sha

aleksandrvk [35]

Answer:

14.6

Step-by-step explanation:

The computation of average price paid for the share is shown below:-

$Average = \frac{Total\ investment}{Total\ share}$

= $\frac{6,000}{410}$

= 14.6

For more clarification please find the attachment as attached using excel spreadsheet.

By dividing the total investment by the total number of shares we can get the average price paid for the share and the same is to be considered

Moreover, the total investment and the total shares are shown in the attachment. Kindly find it below:

4 0

4 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Lubov Fominskaja [6]

Answer: $\sqrt{37}$

=====================================

Work Shown:

6x-y = -3 is the same as 6x-y+3 = 0

6x-y+3 = 0 is the form Ax+By+C = 0 with A = 6, B = -1, C = 3.

The distance d that line is from the point (p,q) = (6, 2) is found by the following

$d = \frac{A*p+B*q+C}{\sqrt{A^2+B^2}}\\\\d = \frac{6*6-1*2+3}{\sqrt{6^2+(-1)^2}}\\\\d = \frac{36-2+3}{\sqrt{36+1}}\\\\d = \frac{37}{\sqrt{37}}\\\\d = \frac{37\sqrt{37}}{37}\\\\d = \sqrt{37}\\\\d \approx 6.08276\\\\$

7 0

3 years ago