Write the number that is 10 less than 526

Mathematics

2 answers:

Leona [35]3 years ago

6 0

To find the answer all you have to do is subtract 10 from 526.

So, 526 - 10 = 516

Hope this helped :)

san4es73 [151]3 years ago

4 0

The number is 516 ......

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xz_007 [3.2K]

Answer:

$Center = \boxed{1}, \: \boxed{ - 2} \: ; \: Radius = \boxed{3}$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 2x + 4y - 4 = 0 \\ \\ ({x}^{2} - 2x + 1 - 1) + ( {y}^{2} + 4y + 4 - 4) - 4 = 0 \\ \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} + 4y + 4) - 9 = 0 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = 9 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = {3}^{2} \\ \\ equating \: it \: with \\ \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ \\ h = 1 \\ k = - 2 \\ r = 3 \\ \\ center = \boxed{1} \: \boxed{ - 2} \: \: radius = \boxed{3}$

3 0

3 years ago

If you know this pls help ):

Aleksandr-060686 [28]

From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)

Hence, we can say that it's:
$\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}$
$= \sqrt[3]{162x^{6}y^{3+d}}$

Hence, c = 6 and d = 2

4 0

3 years ago

How many square inches are 9 cubes with a 1 inch edge

ki77a [65]

Add it up then you will get answer