Answer:
C) Both data sets are multiplicative relationships.
In data set I, y is 2.5 times x, and in data set II, y is 2 times x.
Step-by-step explanation:
When I did y/x, I kept getting a constant number for both data set 1 and 2. This means that they are proportional, so they have multiplicative relationships.
Answer:
22
Step-by-step explanation:
22/2=11
11x2=22
Answer:
We need to earn $10,000 to buy that car.
Step-by-step explanation:
Let initial bank account balance = 0;
Suppose our income is $x.
Since 23% of income shpould be paid in taxes,
Money paid in taxes = 23/100x X
After paying taxes,
Money in our account = Income - Money paid in taxes;
Money in our account = x - 23/100x X
Money in our account = 77/100x X (equation 1)
Given,
Price of the car to be bought = $7700 (equation 2)
To be able to buy that car,
Money in account = Price of the car
From equation 1 and equation 2,
77/100x X = 7700
x= 7700 x 100/77
Therefore,
x = $10000.
Therefore
We need to earn $10000 to buy the car.
Answer:
(-4, 5)
Step-by-step explanation:
The problem is a system of equations where you have two variables and can use the method of eliminate (eliminating one of the variables) to solve. In this case, you will need to multiply one of the fractions by a factor to eliminate a variable. It seems easiest to multiply the first equation by a factor of -5:
-5(x - 3y) = -24 (distribute) -5x + 15y = 120
Add the equations:
-5x + 15y = 120
<u>+5x + 8y = -5</u>
23y = 115 (divide by 23)
y = 5
Solve for 'x': x - 3(5) = -24 or x - 15 = 24 (add 15) x = -4
Ordered pair: (-4, 5)
To get the expected value of student between 700 and 750 we proceed as follows;
z=(x-mean)/SD
thus;
z=(700-750)/50
z=-1
the probability associated with z=-1 is P(x)=0.1587
also;
z=(750-750)/50=0
the probability associated with z=0 is P(x)=0.5000
thus the probability of getting a number between 700 and 750 is:
0.5000-0.1587
=0.3413
thus the number of students students who scored between 700 and 750 will be:
0.3413*2000
=682.6
=683
