Answer:
28
Step-by-step explanation:
9-6/3=9-2=7
4*7=28
X^2 + 6x +9
(x+3) (x+3)
x+3 = 0
x = -3
answer: x=-3
If α and β are the Roots of a Quadratic Equation ax² + bx + c then :
✿ Sum of the Roots : α + β 
✿ Product of the Roots : αβ 
Let the Quadratic Equation we need to find be : ax² + bx + c = 0
Given : The Roots of a Quadratic Equation are 6 and 3
⇒ α = 6 and β = 3
Given : The Leading Coefficient of the Quadratic Equation is 4
Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2
Leading Coefficient of our Quadratic Equation is (a)
⇒ a = 4
⇒ Sum of the Roots 
⇒ -b = 9(4)
⇒ b = -36
⇒ Product of the Roots 
⇒ c = 18 × 4
⇒ c = 72
⇒ The Quadratic Equation is 4x² - 36x + 72 = 0