If the height and radius of a cylinder are doubled, how will the volume of the cylinder be affected?

Find the unknown side lengths in these right triangles.

ivolga24 [154]

Answer:

Triangle 1 - $\sqrt{29$ (if they want simplest radical form) or 5.4 (if they want to the nearest tenth)

Triangle 2- i couldnt figure this one out- may not be true

Pythagorean Theorem is... C) true for all right triangles

Step-by-step explanation:

4 0

3 years ago

I don’t know my answer

Angelina_Jolie [31]

That is why you have an education go to school and learn your anwer.

3 0

3 years ago

Is -33 a whole number?

Jet001 [13]

Answer/Step-by-step explanation:

-33 is not a whole number. A whole number is a number(positive) that contains no decimals nor fractions.

5 0

3 years ago

The indoor climbing gym is a popular field trip destination. This year the senior class at High School A and the senior class at

Tamiku [17]

Answer:

50 students per bus and 9 students per van

Step-by-step explanation:

I just guessed until I got it right, so I don't really have a method. If I ever find a better way of doing it, I'll edit my answer.

7 0

3 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ Given Information :-

⠀

Hypotenuse = 22 ft.
Base = 10 ft.

⠀

✰ To Find :-

⠀

The value of side or the perpendicular

⠀

✰ Formula Used :-

⠀

$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

⠀

✰ Solution :-

⠀

$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$

Thus, option B. 19.60 ft. is the correct option.

⠀

$\underline{\rule{230pt}{2pt}} \\ \\$

4 0

3 years ago