All categories

3 years ago

What is the solution to this system of equations?

Mathematics

2 answers:

wariber [46]3 years ago

8 0

Answer:

A just sub y of first equation into second then solve for X value

taurus [48]3 years ago

7 0

Answer:

A. (2, 6)

Step-by-step explanation:

Whenever a question asks for a solution and the graph is shown, the easiest way to find the solution is to see where the lines intersect. In this case, that would be at the point (2, 6).

You might be interested in

Slope and y intercept of y=2.7x+8

RSB [31]

Answer:

slope: 2.7

y-intercept: (0,8)

Step-by-step explanation:

In the form y = mx + b, m is the slope and b is the y-intercept.

7 0

3 years ago

Read 2 more answers

Please I really need your help

Contact [7]

I know the answer but what lesson is this on

5 0

3 years ago

If using the method of completing the square to solve the quadratic equation x^2 - 9x - 8 = 0, which number would have to be add

V125BC [204]

Answer:

Number: 28.25

Solution to Quadratic: $x=\frac{9}{2}\pm\frac{\sqrt{113}}{2}}$

Step-by-step explanation:

$x^2-9x-8=0$

$x^2-9x-8+28.25=0+28.25$ <-- 28.25 is the number you need to add

$x^2-9x+20.25=28.25$

$(x-4.5)^2=28.25$

$x-4.5=\pm\sqrt{28.25}$

$x=4.5\pm\sqrt{28.25}$

$x=\frac{9}{2}\pm\sqrt{\frac{113}{4}}$

$x=\frac{9}{2}\pm\frac{\sqrt{113}}{2}}$

6 0

3 years ago

How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap

Ivan

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal. For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

6 0

3 years ago

Consider a bettering game where you bet $10 and have a probability of 0.45 of getting $20 back ($10 more than you started with)

Marina CMI [18]

Answer:

(a)

$f(x) = P(X=x) = \begin{Bmatrix} 0.45 \,\,\, \text{for} \,\,\, x = 10 \\ 0.55 \,\,\, \text{for} \,\,\, x = -10 \end{matrix}$

(b)

-1

(c)

Step-by-step explanation:

(a)

Your random variable will have two possible values, 30 and 0, one of them with a probability of 0.45 and the other one with a probability of 0.55. Therefore it looks like this.

$f(x) = P(X=x) = \begin{Bmatrix} 0.45 \,\,\, \text{for} \,\,\, x = 10 \\ 0.55 \,\,\, \text{for} \,\,\, x = -10 \end{matrix}$

(b)

The expected value of this PMF would be

$E[X] = -10*0.55+10*0.45= -1$ therefore on average you will have a dollar less.

(c)

For this one, if you play 20 times and your initial amount is 50$ then you have to compute the following expectation.

$E[50+20*X] = 50+20*E[X] = 50-20 = 30$

7 0

3 years ago