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Dvinal [7]
3 years ago
13

How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap

proximate the​ 95% confidence interval of the population proportion
Mathematics
1 answer:
Ivan3 years ago
6 0

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal.  For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

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