You're given the slope of the line and a point thru which the line passes. So it makes sense to use the point-slope form of the equation of a straight line: if the point is (a,b) and the slope is m, then
y-b=m(x-a). You'd then solve this for y to obtain the equation in slope-intercept form.
On the other hand, if you're asked to write the equation in slope-intercept form, starting with the general form of this equation may be faster: y=mx+b.
Substitute the given values for x and y (which are 25 and -9) and m (which is (2/5). Solve the resulting equation for b (the y-intercept).
Then write the finished equation: y=( ? )x + b, where b is the y-intercept you've just found.
Everything that is not 4/9
Answer:
Step-by-step explanation:
An x value of 0 can only be plugged into the equation that has a domain that includes 0. The first function's domain is between -2 and -4, so 0 is not included in that domain. In the third function, the domain is between 1 and 3, so 0 is not included in that domain, either. The middle function's domain does include 0 (0 falls between -2 and 1) so we can only evaluate this function at an x value of 0.
g(0) = -0 - 1 so
g(0) = -1
Answer:
<h3>Sv is angle bisector of rst.</h3>
