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diamong [38]
3 years ago
8

Can somone pls help me .. i will mark u brainliest !

Mathematics
1 answer:
frutty [35]3 years ago
6 0

Answer:

1. D

2. A

3. B

Step-by-step explanation:

1. Add exponents

2. Multiply exponents to outside exponent and to the 16

3. Distribute exponents

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150% of 48 as a percent
frosja888 [35]

Answer:

72, 150%

Step-by-step explanation:

8 0
4 years ago
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How man significant dogits are in there in the product if 45.10 and 101?
tester [92]
3 significant digits
8 0
3 years ago
2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)
Reptile [31]

Answer:

f(x)=x^2-x-12

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

f(x)=a(x-x1)(x-x2)

Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

\boxed{f(x)=x^2-x-12}

5 0
3 years ago
PLEASE MAKE SURE YOU GIVE WORKING AND AN EXPLANATION FOR YOUR ANSWER Question) The sum of the integers from -2015 to 2017 is (A)
yKpoI14uk [10]

Answer:  (A) 2

The sum of the integers from -2015 to 2017  = 2

Step-by-step explanation:

The sum of integers a and b is represented as a+b.

The sum of the integers from -2015 to 2017  = -2015+2017

Since -a+b=b-a

Thus, The sum of the integers from -2015 to 2017  = 2017-2015 = 2

i.e.  The sum of the integers from -2015 to 2017  = 2

Thus , the correct option is (A).

6 0
3 years ago
Solve the inequality for x. Show each step of the solution.10x &gt; 2(8x – 3) – 18
Luden [163]

Answer: x<4

Given the inequality:

10x>2(8x-3)-18

We want to solve the inequality for x.

First, distribute the bracket on the right side of the inequality.

\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}

Next, subtract 10x from both sides of the inequality.

\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}

Add 24 to both sides of the inequality.

\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}

Divide both sides of the inequality by 6.

\begin{gathered} \frac{24}{6}>\frac{6x}{6} \\ 4>x \\ \implies x

The solution to the inequality is x<4.

6 0
1 year ago
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