The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
1.17 + 2.65p = 9
2.65p = 9 - 1.17
2.65p = 7.83
p = 7.83/2.65
p = 2.95.......maximum number of pens Linda can buy is 2
Answer:
H
Step-by-step explanation:
here, the question says that the given regular hexagon needs to be rotated counter clockwise 300°, considering the edges labels, each movement from one edge to other is 60° as 360/6 =60.
focus on N and move on anti clockwise.
When N rotates anti clockwise about center from original to position G, is 60°,
when N moves on anti clockwise about center from original to position A is 120°.
similarly, to X is 180°, to E is 240° and to H is 300°.
so, the new position of N when rotated anti clockwise about origin of the hexagon will be at H.
Answer:
x = -5
Step-by-step explanation:
Hope this helps.
Answer:
0.79
Step-by-step explanation:
