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3 years ago

‼️Problem Solving‼️

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

Answer:

12 hours

Step-by-step explanation:

He earns R150 per hour and he wants to earn R1800:

1800/150 = 12

He must work 12 hours to earn R1800.

enot [183]3 years ago

5 0

Step-by-step explanation:

150/1800

=12

he must work 12 hours to earn rs.1800

mark me as brainliest if this helps to u

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Question number one is 2/3

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3 years ago

Evaluate 1/3m-1-1/2n when m=21 and n=12

siniylev [52]

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3 years ago

What will be the sign of the operation between the two terms in the squared binomial?

Allushta [10]

Answer:

We can find the square by multiplying the binomial by itself. However terms Lastly, we see that the first sign of the trinomial is the same as the sign of the binomial. For the middle term of the trinomial, double the product of the two terms.

Step-by-step explanation:

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3 years ago

A scientist makes $150,000 per year. She deposits 5% of her yearly income in a travel savings account. How much money should she

frez [133]

Answer:

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plz mark me as brainly

Step-by-step explanation:

3 0

3 years ago

The coordinates of the vertices of a rectangle are (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

SCORPION-xisa [38]

Answer:

Perimeter of rectangle is 23.34

Step-by-step explanation:

The coordinates of the vertices of a rectangle are (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

What is the perimeter of the rectangle?

The formula to find perimeter of rectangle is: $Perimeter=2(l+w)$

We need to find length and width first using the coordinates (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

Let A=(-4, 3) B=(-1, 5) C=(3, – 1) and D=(0, – 3) according to the figure attached.

So, If we find distance of point AB it can be considered length of rectangle and distance of point AC can be considered width of rectangle

The formula used to find distance is: $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Finding distance AB, we have $x_1=-4, y_1=3, x_2=-1, y_2=5$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(-1-(-4))^2+(5-3)^2}\\Distance=\sqrt{(-1+4)^2+(5-3)^2}\\Distance=\sqrt{(3)^2+(2)^2}\\Distance=\sqrt{9+4}\\Distance=\sqrt{13}\\Distance=3.61$

So distance between point A and B is 3.61

Finding distance AC, we have $x_1=-4, y_1=3, x_2=3, y_2=-1$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(3-(-4))^2+(-1-3)^2}\\Distance=\sqrt{(3+4)^2+(-1-3)^2} \\Distance=\sqrt{(7)^2+(-4)^2} \\Distance=\sqrt{49+16} \\Distance=\sqrt{65}\\Distance=8.06$

So, distance between point A and C is 8.06

We have length = 3.61 and width = 8.06

Using formula of perimeter

$Perimeter=2(l+w)\\Perimeter=2(3.61+8.06)\\Perimeter=2(11.67)\\Perimeter=23.34$

So, Perimeter of rectangle is 23.34

6 0

3 years ago