PQ is bisected by line <em>L</em>.
so the answer is C
PQ=14
Step-by-step explanation:
5x-3=11-2x
5x+2x=11+3
7x=14
x=2
replace X in any of the given distance equation then multiply by 2 since the distance Pm=Qm
PQ=2(11-2x)
2(11-2(2))
2(7)
Therefore PQ=14
Sec^2 x - 1 = tan^2x
Proof:
Sec^2x = 1+ tan^2x
1/cos^2x = 1 + sin^2x/cos^2x
<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting :
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side
It falls between two and three because it's 2.6
i think this is the answer
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