1. The problem statement tells you it took 1 hour for Samantha to realize she forgot her wallet.
2. Samantha speed-walked back to the car at twice the speed she was originally walking, so it took her half the time, 1/2 hour.
3. Samantan jogged the 10 mile distance at 5 miles per hour. It took her
(10 mi)/(5 mi/h) = 2 h
to get to Buckville.
4. Assuming you want the total time it took Samantha to get to Buckville, it would be
(1 h) +(1/2 h) +(2 h) = 3 1/2 hours
5. Samantha was farthest from Buckville when she was at her car, a distance of 10 miles from Buckville.
6. At 2 miles per hour, the hour Samantha initially walked toward Buckville took her 2 miles. She retraced that 2 miles, then jogged 10 miles, for a total of ...
2 mi +2 mi +10 mi = 14 miles
Answer:
A : 4.5
B: 1 4/5
E: 26
L:91
W: 5
H: 72.2
T: 11
M: 999
Step-by-step explanation:
hope this helps!!
9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
__
In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
Brenda>tim>carl>ali
Brenda was closer to the surface and all was further from the surface.
The slope is
2-1
m = rise / run = ------- = -1/2
1-3