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konstantin123 [22]
3 years ago
8

If an athletic field is a rectangle it is 120 yards x 6 yards with a semi circle at each of the ants a running track 15 yards wh

y surrounds I feel how many yards of fencing do you need Tessaro outside age of the track
Mathematics
1 answer:
marta [7]3 years ago
4 0
So Im not sure about the english here and 6 yards doesnt really make sense but given the info you gave me:

The length of the outside is 120+15*2 and the width of the outside is 6+15*2 so you get a perimeter of 150*2+36*2=372

Are you sure the 6 isnt supposed to be 60? That would make more sense...
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7 1/2 sticks of butter are needed to make 5 cakes. How much butter is needed to make one cake?
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Answer:

1 1/2

Step-by-step explanation:

because when you divide 7.5 by 5 you get 1.5

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Step-by-step explanation:

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Lena's engagement ring has a radius of 9 millimeters. What is the ring's circumference? Use 3.14 for ​
scoray [572]

Answer:

Given - Radius of ring is 9 millimeters

To find - Circumference

Solution -

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3 years ago
Determine the measure of angle A, to the nearest degree.
Effectus [21]

Answer:

(a) 17°

(b) 78°

Step-by-step explanation:

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A= sin^-1(0.2896) = 16.83

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2 years ago
Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

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Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: \lambda=2\cdot 2.1=4.2

P(X\geq 5)=1-P(X

Therefore, the probability is P=0.410.

4 0
3 years ago
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