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hjlf
3 years ago
5

A=1/2 bh (base/height) =.5(12)4 a=24ft how did i get the answer a=24?

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0
That’s what i got
step by step explanation
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What are the two square roots of 1/49?
ololo11 [35]
The answer is 1 and 7
7 0
3 years ago
Simplify the expression 6C5.<br> a.6.<br> b. 24<br> C. 30<br> d. 720
Lana71 [14]
<h3>Answer:  A) 6</h3>

=====================================================

Explanation:

Plug n = 6 and r = 5 into the nCr combination formula

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_6 C _5 = \frac{6!}{5!*(6-5)!}\\\\_6 C _5 = \frac{6!}{5!*1!}\\\\_6 C _5 = \frac{6*5*4*3*2*1}{5*4*3*2*1*1}\\\\_6 C _5 = \frac{720}{120}\\\\_6 C _5 = 6\\\\

Or you could use the shortcut

_n C _{n-1} = n\\\\

Yet another path you could take is to use Pascal's Triangle. Locate the row that starts with 1,6,... and then locate the second to last item. That value in the triangle is 6.

A real world interpretation is to consider having 6 people and you are selecting 5 of them to form a group where order doesn't matter. How many ways are there to do this? Well there are 6 such ways because there are 6 ways to leave someone out of the group.

8 0
2 years ago
Help plz i need hel-p im so stuck man im lost
Gwar [14]

Answer:

t = 50

Step-by-step explanation:

EI = EG

2t - 79 = t - 29

t - 79 = -29

t = 50

5 0
3 years ago
Which function does not have a vertical asymptote? A) y=(x) /(1-x²) . B) y=(5x) /(1-2x²) . C) y=(5x-1) /(3+x^2) . D) (5x) /(x+x²
uysha [10]

A function has a vertical asymptote x=a at point a, where the denominator becomes equal to 0.

A. The denominator of the function f(x)=\dfrac{x}{1-x^2} turns into 0 at x=1 or x=-1. Then x=1 and x=-1 are two vertical asymptotes of this function.

B. The denominator of the function f(x)=\dfrac{5x}{1-2x^2} turns into 0 at x=\sqrt{\frac{1}{2}} or x=-\sqrt{\frac{1}{2}}  Then x=\sqrt{\frac{1}{2}}  and x=-\sqrt{\frac{1}{2}}  are two vertical asymptotes of this function.

C. The denominator of the function f(x)=\dfrac{5x-1}{3+x^2} never turns into 0, then this function hasn't any asymptotes.

D. The denominator of the function f(x)=\dfrac{x}{x+x^2} turns into 0 at x=0. Then x=0 is vertical asymptote of this function.

Answer: correct choice is C.

5 0
3 years ago
How does a line differ from a segment line?
Trava [24]
A line has an arrow on each end of the line. A segment has a dot or point on each end of the line.
5 0
3 years ago
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