There can't be more than seven $5 bills, because they would be worth $33.
So, let's try all other cases and see which fits the requests:
- If there are six $5 bills, they are worth $30. You need three more $1 bills to reach $33. So, you have a total of 9 bills, which is not what we want.
- If there are five $5 bills, they are worth $25. You need eight more $1 bills to reach $33. So, you have a total of 13 bills, which is not what we want.
- If there are four $5 bills, they are worth $20. You need thirteen more $1 bills to reach $33. So, you have a total of 17 bills, which is not what we want.
- If there are three $5 bills, they are worth $15. You need eighteen more $1 bills to reach $33. So, you have a total of 21 bills, which is not what we want.
- If there are two $5 bills, they are worth $10. You need twenty-three more $1 bills to reach $33. So, you have a total of 25 bills, which is not what we want.
- If there is one $5, it is worth $5. You need twenty-eight more $1 bills to reach $33. So, you have a total of 29 bills, which is not what we want.
So, there's no way you can have 31 bills worth $1 and $5 that are worth $33 in total.
No because really it’s not explains nothing
Math and english give you a total of 4 hours. and social studies and science gives you a total of 2 3/4 hours. add them up, and the closest he will spend to studying is 7 hours
Answer:
QR = 48 units
Step-by-step explanation:
in a rectangle, opposite sides are equal
so QR = PS and QP = RS
also we know that the sum of all sides is the perimeter, which is 176
we can set up this equation:
2(5z - 2) + 2(4z) = 176
10z - 4 + 8z = 176
18z - 4 = 176
18z = 180
z = 10
QR = 5z - 2
we can substitute 10 for 'z' to get:
5(10) - 2 = 50 - 2 or 48
Check:
2(48) + 2(40) = 176
96 + 80 = 176
176 = 176
Answer:
No. The solution is 
Step-by-step explanation:
