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coldgirl [10]
3 years ago
7

Item 7 Solve the equation. x+12=7

Mathematics
2 answers:
kherson [118]3 years ago
7 0

Answer:

x= -5

Step-by-step explanation:

7-12=-5 so x= -5

MA_775_DIABLO [31]3 years ago
5 0
7 - 12 = -5 so x = -5
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Hey there!

1/2 x 4/4 = 4/8

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1 year ago
Read 2 more answers
At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round
sweet [91]

Answer:

Meeting\ Time = 6:03\ pm

Step-by-step explanation:

Given

Start\ Time= 5:45pm

Lixin = 18\ min/round

Khairul = 360\ seconds/round

Devi = 4minutes/2\ rounds

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

Lixin = 18\ min/round

Khairul = 360\ seconds/round

Convert 360 seconds to minutes

Khairul = \frac{360}{60} min/round

Khairul = 6 min/round

Devi = 4minutes/2\ rounds

Divide by 2/2

Devi = 2mins/round

So, we have:

Lixin = 18\ min/round

Khairul = 6 min/round

Devi = 2mins/round

Next, is to determine the LCM of 18, 6 and 2

18=2 * 3 * 3

6 = 2 * 3

3 = 3

Their LCM is:

LCM = 2 * 3 * 3

LCM = 18

This means that they will meet 18 minutes after their initial time of departure.

So:

Meeting\ Time = 5:45\ pm + 18\ minutes

Meeting\ Time = 6:03\ pm

3 0
3 years ago
Vector u has its initial point at (21,12) and its terminal point at (19,-8). Vector v has a direction opposite that of u, whose
agasfer [191]

Step-by-step explanation:

517÷4685568π√7%+66×74367

7 0
3 years ago
The graph shows a function. Is the function linker or non linear?
zloy xaker [14]

Answer:

It is linear since it is a straight line.

8 0
2 years ago
To rent a jet ski at Hayden’s cost is $25 plus $3 per hour. At Austin’s, it costs $5 plus $8 per hour. At how many hours will th
Katen [24]
<u>At Hayden's:</u> 

(25+3)= \ 28+3 \ (2nd \ hour)=31+3 \ (3rd \ hour)=34+3 . . . \swarrow\swarrow \\ \ \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow  \boxed{34+3=37}= \ (4rth \ Hour)

<u>At Austins:</u> 

(5+8)= \ (first \ hour) = 13+8= \ 21 = (2nd \ hour) \ 21+8=29= \ \swarrow \\ \longrightarrow \ 29=(3rd \ hour)=\boxed{ 29+8= (37)= \ ((Forth \ hour))}

As we can see in both results, it would take them (4 hours) for the prices to be equaled.
3 0
3 years ago
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