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3 years ago

15

a store has 18 red beach balls and 17 green beach balls in boxes of 5 beach balls each how many boxes of beach Balls are in stor

e?

2 answers:

polet [3.4K]3 years ago

6 0

There are seven [7] boxes in the store.

Stells [14]3 years ago

4 0

10 beach balls are needed

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Incline Electronics produces three different products in a plant that is open 40 hours per week. Each product requires the follo

Paladinen [302]

Answer:

is thier any way you can take a picture of what the problem is cause alot of the equation are not adding up the way you put them

8 0

2 years ago

PLEASE HELP!! I’ll make you the brainlyest!!!

STatiana [176]

Answer:

15

Step-by-step explanation:

Can't really see the graph clearly but the range looks like its from 40-70 so 30 and the amplitude is half of that so 15.

6 0

2 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

3 years ago

Solve for h please and thank you

KonstantinChe [14]

Answer:

35° (I may be wrong)

Step-by-step explanation:

An isosceles triangle has an interior angle sum of 180° (like all triangles).

So...

180°-40°= 140°

And because we know that isoceles triangles and two congruent sides, we just have to divide 140° by 2.

140°÷2=70°

But the picture says 2h and h is a side so...

70°÷2=35°

4 0

3 years ago

Which value of b would make 16x²-bx + 25 a perfect square trinomial?

blondinia [14]

Answer:

b = 40 and -40

Step-by-step explanation:

General form of Perfect square trinomial is a 2 + 2 a b + b 2

Therefore from 16 x 2 − b x + 25 a 2 = √ 16 x 2 , b 2 = 25 , then a = ± 4 x , b = ± 5 take consideration a=4x and b=-5 (different sign), then − b x = 2 ( 4 x ) ( − 5 ) − b x = − 40 x b = 40

The perfect square is ( 4 x − 5 ) 2 = 16 x 2 − 40 x + 25 .

if we consider a=4x and b=5 (same sign), then − b x = 2 ( 4 x ) ( 5 ) − b x = 40 x b = − 40

The perfect square is ( 4 x + 5 ) 2 = 16 x 2 + 40 x + 25 .

The first solution ( 4 x − 5 ) 2 is the best solution after comparing the expression given. I hope this helps, xx .

8 0

3 years ago