Part A.
The trip starts at 8am which corresponds to 0 hrs, point (0hr, 0mi)
2hrs later it's 10am. .point (2hr, 140mi)
The average speed is the slope between 0 and 2 hrs. Remember the slope formula m = Δy/Δx
m = (140 - 0) / (2 - 0)
m = 70 mph
Part B. Average speed from 11am - 2pm
11am is point (3hr, 140mi)
2pm is point (6hr, 300mi)
As you can see from the graph, the speed or slope changes at 1pm (5,260). You Can just use the start and end points.
m = (300-140) / (6-3)
m = 160/3
53.3 mph
* It comes out the same solution as if you average the two different slopes. 2hrs at 60mph + 1 hr at 40mph = (120 + 40)/3 = 160/3
Part C. Total average speed = total distance / total time driving
He went 70 mph for 2 hrs
stopped for an hour (slope is zero, no speed)
60 mph for 2hrs
40mph for 1 hr
300mi /5hr = 60mph
Part D. No Question....
Answer:
Yes
Step-by-step explanation:
Reason is that a square has all the aspects of a parallelogram a rectangle and a rhombus. It gets its congruent diagonals from the rectangle which is congruent
Answer:
Your answer: 87
Step-by-step explanation:
Since you are given what both variables are in the equation, this problem requires you to plug it in.
12(6)+3(5)= ?
You can either do this in a calculator, or do this one step at a time.
12(6)=72
3(5)=15
72+15=87
Answer: 40
Step-by-step explanation:
Number of correct questions Sally got = 28 questions
Percentage of correct questions answered= 70% on the exam,
Total number of questions in the exam = Unknown
Let the total questions in the exam be represented as y.
Since Sally got 70% correctly, this will be:
70% of y = 28
70/100 × y = 28
0.7 × y = 28
0.7y = 28
Divide both side by 0.7
0.7y/0.7 = 28/0.7
y = 40
There are 40 questions in the exam.
<span>1/2-(5/4) = x+1/4 // - x+1/4
1/2-x-(5/4)-(1/4) = 0
1/2-x-5/4-1/4 = 0
-x-1 = 0 // + 1
-x = 1 // * -1
x = -1
x = -1
</span>
