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Allushta [10]
3 years ago
7

Determine mode and median​

Mathematics
2 answers:
saveliy_v [14]3 years ago
7 0
Mode is the total average median is the middle number
malfutka [58]3 years ago
5 0

Answer:

mode is {15-20) as it has high frequency.

class x frequency F. CF

5-10. 5. 5

10-15. 7. 12

15-20. 11. 23

20-25. 8. 31

25-30. 10. 41

30-35. 3. 44

35-40. 2. 46

N=46

median =(N/2)th term =46/2=23 th term

in CF column just equal to 23 is 23

median class =(15-20)

median =15+ (23-12)/11×5=20

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The grades are given for a student for a particular term. find the grade point average. the point values of grades are given bel
Angelina_Jolie [31]
C. I think so I don't know but that's what I think...
6 0
3 years ago
Helpppp a girl outtt i will give brainlest
Ivenika [448]

Answer:

Y= 40

Step-by-step explanation:

I know the y equals 40 because I used

a {}^{2}  + b {}^{2}  = c {}^{2}

But for z and x I got stuck, so I hope I helped you a little to move forward with this problem.

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7 0
3 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
The average winter snowfall in City A is 105 cm. City B usually gets 2.8 m of snow each winter. Compare the yearly snowfall in t
Inessa [10]
We see that city A gets 105 cm of snow while city B gets 2.8 m. The first thing we do is make both measurements equal to each other. This can be done by either converting city A's 105 centimeters to meters or city B's meters to centimeters. But the question specifically calls for both, so we get both measurements.

City A: 105 centimeters OR 1.05 meters
City B: 280 centimeters OR 2.8 meters

Now that we know the measurements, let's look at the first problem. (A) asks for the difference in one year in meters. The difference of course means subtraction. Now it's here where I personally am confused on what it asking for in terms of which city is it asking for us to subtract from, but using an educated guess, I'll say we're subtracting from city B because if we were to subtract from city A, we'd have a negative, and you can't have a negative amount of snow, only 0 snow.

So once again, for question (A), we subtract 1.05 from 2.8 (2.80 - 1.05) and we get 1.75 meters of snow.

Question (B) asks for the difference during two years in centimeters, so we multiply both measurements by 2 and use the centimeter measurements. (105 x 2 = 210) (280 x 2 = 560) Subtract 560 from 210 (560 - 210) and we get 350 centimeters.

So your answers are: (A) 1.75 meters (B) 350 centimeters

I hope this helps!
5 0
4 years ago
What is the answer to 93+(68+7)
Novosadov [1.4K]
 you can use the distributive property
assume a 1 in front of the prenthasees

93+1(68+7)
distribute
93+68+7
use communtative property to move around
93+7+68
add
100+68
168
commutative and distributive
3 0
3 years ago
Read 2 more answers
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