1. Place these numbers in order from smallest to largest:

one year ago, Charlie's chameleon was 8.42 inches long. Now his chameleon is 9.36 inches long. a.how much did Charlie's chameleo

Delicious77 [7]

The chameleon grew .94 inches, and would need to grow .64 inches to be exactly 10 inches.

3 0

3 years ago

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PLS HELPPPPPPPPPPP :p 8*10^3 is how many times larger that 4*10^2?

Cloud [144]

Answer:

20 times.

Step-by-step explanation:

To find out how many times larger a number is than another number, simply divide the two numbers, with the larger number being in the numerator.

For example, how many times larger is 6 than 2? The answer would be 6/2 or 3 times larger.

So, divide 8*(10^3) and 4*(10^2):

$\frac{8\times10^3}{4\times10^2}$

Expand the expressions. This is the same as saying:

$\frac{8\times10\times10\times10}{4\times10\times10}$

We can cancel two of the 10s since they are in both the numerator and the denominator. Thus, only one 10 is left in the numerator:

$\frac{8\times10}{4}$

Simplify:

$=\frac{80}{4} =20$

Therefore, 8*(10^3) (or 8000) is 20 times larger than 4*(10^2) (or 400).

7 0

3 years ago

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Line AB contains points A(4, 5) and B(9, 7). What is the slope of Aß?

Anvisha [2.4K]

<em>Let the common root is ‘x’</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1⇒ {1 + a + b = 0} (From equation (1))</em>

<em>Let the common root is ‘x’x2 + ax + b = 0 ……(1)x2 + bx + a = 0 ……(2)Subtract equation (2) from (1), we get(a – b)x + (b –a) = 0⇒ x = (a-b)/(a-b) = 1⇒ x = 1⇒ {1 + a + b = 0} (From equation (1))⇒ a + b = –1</em>

3 0

3 years ago

If you roll a dice four times, what is the chance that you roll two 3s?

Rufina [12.5K]

Answer:

11.57%

Step-by-step explanation:

The probability of rolling two 3s is the product of the probability of rolling two 3s and two not-3s, and the number of ways that combination of rolls can appear.

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<h3>combinations of rolls</h3>

Of the four die rolls, we want two of them to be 3s. The 3s can appear anywhere in the sequence. For example, we could have 33xx, or xx33, or any of a number of other combinations (where x is a "not 3"). The total number of ways two 3s can appear an a sequence of 4 rolls is ...

C(4, 2) = 4!/(2!(4 -2)!) = 4·3/(2·1) = 6

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<h3>probability of two 3s and two not-3s</h3>

The probability of rolling a 3 on a fair 6-sided die with one face labeled 3 is presumed to be 1/6. Then the probability of rolling something else is ...

1 -1/6 = 5/6

So, two 3s and two not-3s in a given sequence have a probability of ...

(1/6)(1/6)(5/6)(5/6) = 25/1296

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<h3>two 3s in 4 rolls</h3>

The probability that four rolls of the die will show exactly two 3s is the product of the probability it can happen and the number of ways it can happen:

(25/1296) × 6 = 25/216 ≈ 11.57%

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The attachment shows the probability function of a calculator gives the same result.

3 0

3 years ago

I had 16 ounces of chocolate I used 2/5 of the chocolate how much more chocolate did I have left

chubhunter [2.5K]

Used 2/5 of the chocolate.

= 2/5 * 16

= 32/5

= 6.4

Ounces left = 16 - 6.4 = 9.6

9.6 ounces of chocolate left.

6 0

3 years ago