Question

A hot air balloon is flying at a constant speed of 20 mi/h at a bearing of N 36° E. There is a 10mi/h crosswind blowing due east. What is the balloon's actual speed and direction? Round angles to the nearest degree and other values to the nearest tenth.

Answer 1

Answer:

Step-by-step explanation:

v = {[(20sin36°)i + (20cos36°)j] + 10i} mi/h

 

vE = 20sin36º + 10 = 21.76 mi/h

 

vN = 20cos36° = 16.18 mi/h

 

v = √(vE2 + vN2) = √(21.762 + 16.182) mi/h = 27.12 mi/h

 

θ = tan-1(vN/vE) = tan-1(16.18/21.76) = 36.6º north of east