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soldi70 [24.7K]
2 years ago
12

carol and jada sold raffle tickets to raise money for a new playground carol sold 2045 tickets jada sold 356 more than carol how

many did jada sell​
Mathematics
1 answer:
GenaCL600 [577]2 years ago
4 0
Jada sold 2401 tickets
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Which terms could be used as the first term of the expression below to create a polynomial written in standard form? Select five
vovikov84 [41]

Option C: -6rs^5

The last two terms given of the standard polynomial are:

\cdots + 8r^2s^4 +  3r^3s^3

This shows 2 patterns to us:

r 's degree is increasing per term in the given polynomial.

s 's degree is decreasing per term in the given polynomial.

The sum of powers of variates r and s is 2+4 = 3+3  = 6.

And since standard polynomial, the same pattern must be present in all terms of the series.

All options except C are not valid.

Option C has term -6rs^5 for which r's degree plus s's degree is 1 + 5 = 6.

And r's degree 1 <  s's degree 5.

Thus its a valid term to be putted as first term in standard form of polynomial in consideration.

Thus Option C: -6rs^5  is the needed expression.

Learn more here:

brainly.com/question/10127580

4 0
2 years ago
Determine the utilization and the efficiency for each situations:A. A loan processing operation that processes an average of 7 l
Vera_Pavlovna [14]

Answer:

A) Utilization = 70%

Efficiency = 87.5%

B) Utilization = 66.67%

Efficiency = 80%

Step-by-step explanation:

Determine the utilization and the efficiency for each situations:

A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = 7 loans per day

Design capacity = 10 loans per day

Utilization = 7/10 × 100

= 70%

Efficiency = Actual output / Effective capacity × 100

Actual output = 7 loans per day

Effective capacity = 8 loans per day

Efficiency = 7/8 × 100

= 87.5%

B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = four furnaces a day

Design capacity = six furnaces a day

Utilization = 4/6 × 100

= 66.67%

Efficiency = Actual output / Effective capacity × 100

Actual output = four furnaces a day

Effective capacity = five furnaces a day

Efficiency = 4/5 × 100

= 80%

6 0
2 years ago
If f(2) =20 and f(3) =10<br>F(4) = ,f(5)=
Arada [10]
F(4)=0 and F(5)= -10
5 0
3 years ago
Simplify -(-2a + 13) + (-9a - 2) - (-7a - 3)
nadya68 [22]
-12 hope it helps :)
5 0
3 years ago
Read 2 more answers
radium-226, which has a half-life of 1620 years, is used in medicine for treatment of disease. find the value of k for radium-22
sammy [17]
There will be a 25 grams left after 3240 years.

The half-life of Radium-226 is 1620 years. If we divide 3240 by 1620 the answer is 2. So that means the amount of Radium-226 will divide in half twice.

100 / 2 = 50 / 2 = 25
6 0
3 years ago
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