Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
Mon - Fri: 4 days 4*30 = 120 bars given away. 225 - 120 = 135 bars
Step-by-step explanation:
1mi = 5280feet
The first thing you should do in this case is to calculate the perimeter of the rectangle which will be given by:
P = 2 * L + 2 * W
Where
L = long
W = width
Calculating we have:
P = 2 * (1/4) + 2 * (1/8)
P = 1/2 + 1/4
P = 3/4 mi
To calculate this distance to feet we have to use the following expression:
(3/4) / (x) = 1/5280
answer:
<span> B) 3/4 miles divided by x= 1 mile/5280ft
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Answer:
0.6 km/hr
Step-by-step explanation:
Speed downstream: 13/5= 2.6 km/hr
Speed upstream: 7/5= 1.4 km/hr
Therefore, Velocity of current is: 1/2 (2.6-1.4) km/hr = 1/2(1.2) km/hr
Answer:
Step-by-step explanation:
Direct proportion
60: 1 5 /12 = 120 : x
60: 17/12 = 120:x
Product of extremes = product of mean
60*x = (17/2)*120
It will take 2 5/6 hours to read 120 pages
