How do you solve: 81 X 9^(-2b-2)=27

2 answers:

6 0

b=−0.75

If the X means times then this is your answer

Step 1: Divide both sides by 81.

Step 2: Solve Exponent.

b=−0.75

5 0

Did you mean

81* 9∧(-2b-2)=27 => First divide whole equation with 81 and get

(3∧2)∧(-2b-2)=1/3 => 3∧(-4b-4)=3∧(-1) => -4b-4=-1 => -4b= -1+4 => -4b=3 =>

we will multiply whole equation with (-1) and get 4b=-3 => b=-(3/4)

If the start item is correct.

Good luck!!!

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vlabodo [156]

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3 years ago

jeka57 [31]

Answer:

$\displaystyle f'(-3) = \frac{7}{9}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Calculus

Derivatives

Derivative Notation

Derivative of a constant is a 0

Basic Power Rule:

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

$\displaystyle f(x) = \frac{-7}{x}$

$\displaystyle x = -3$

Step 2: Differentiate

Quotient Rule: $\displaystyle f'(x) = \frac{\frac{d}{dx}[7]x - \frac{d}{dx}[x](-7)}{x^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{(0)x - x^{1 - 1}(-7)}{x^2}$
Simplify: $\displaystyle f'(x) = \frac{(0)x - x^0(-7)}{x^2}$
Simplify: $\displaystyle f'(x) = \frac{(0)x - 1(-7)}{x^2}$
Multiply: $\displaystyle f'(x) = \frac{0 + 7}{x^2}$
Add: $\displaystyle f'(x) = \frac{7}{x^2}$