To factor this fraction, you have be be aware of two special factoring formula:
a^3<span> + </span>b^3<span> = (</span>a<span> + </span>b)(a^2<span> – </span>ab<span> + </span>b^2<span>)
</span><span>(a+b)³ = a³ + 3a²b + 3ab² + b³
You can see the top part in this case is (x+y)^3, and the bottom (denominator) can be factor into (x+y)(x^2-xy+y^2)
we can cancel (x+y), so what we have left is (x+y)^2/(x^2-xy+y^2)
or (x^2+2xy+y^2)/(x^2-xy+y^2)
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I have to say a because the problem is continuing
58 - its simple- Hope I helped :)
It seems as if D is the answer
The law of sines is usually written as
[sin (A) / a] = [sin (B) / b] which can be manipulated algebraically as
[b * sin (A) / sin (B)] = a
