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3 years ago

What’s the formula to find the shaded area?

Mathematics

2 answers:

Natalka [10]3 years ago

4 0

Answer:

Shaded area = 123.84

Step-by-step explanation:

Shaded area = 576 - 452.16

Shaded area = 123.84

trapecia [35]3 years ago

3 0

shaded area = area of outer figure - area of inner figure........

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A bucket that weighs 4lband a rope of negligible weight are used todraw water from a well that is 80ftdeep. The bucket is filled

liq [111]

Answer:

Workdone = 3200 lb.ft

Step-by-step explanation:

We are told that the bucket is filled with 40 lb of water but water leaks out of a hole in the bucket at a rate of 0.2lb/s

Thus,

Weight of water at any given time (t) would be;

w(t) = 40 - 0.2t - - - - (1)

We are told the bucket is pulled up at a rate of 2ft/s.

Thus, height at time (t); y = 0 + 2t = 2t

Since y = 2t,

Then,t = y/2

Put y/2 for t in eq 1

Thus; w(y) = 40 - 0.2(y/2)

w(y) = 40 - 0.1y

Now, at y = 80 ft, we have;

w(80) = 40 - 0.1(80)

w(80) = 40 - 8 = 32 lb

Since 32 lbs are left, it means there is always water in the bucket.

Thus, work done is;

W = 80,0[∫(Total weight).dy]

W = 80,0[∫[(weight of rope) + (weight of bucket) + (weight of water)]dy]

W = 80,0[∫[0 + 4 + 40 - 0.1y]dy]

Integrating, we have;

W = [44y - y²/20] at boundary of 80 and 0

So,

W = [44(80) - 80²/20] - [0 - 0²/20]

W = 3200 lb.ft

8 0

3 years ago

Please find x.............

emmasim [6.3K]

Answer:

$\underline{\boxed{ x=50}}$

Step-by-step explanation:

$164 = x + 114 \\ x = 164 - 114 \\ x =50$

4 0

3 years ago

(ASAPPP) The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the

prohojiy [21]

Answer:

The instantaneous velocity at $t = 2$ is $-6$ .

Step-by-step explanation:

We have the position as the function

$s(t) = -2 - 6t$

As we know that the velocity is the rate of change of position over time, so it is basically the derivative of the function.

so finding the derivate of $s(t) = -2 - 6t$

∴ $s'(t)=-6$

The instantaneous velocity at $t = 2$

$s'(2)=-6$

Therefore, the instantaneous velocity at $t = 2$ is $-6$ .

Please note that the negative value indicates the direction of movement, in this case, it would be backward.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=4x%20%7B%7D%5E%7B2%7D%20%20%2B%2020x%20%2B%2025" id="TexFormula1" title="4x {}^{2} + 20x + 25

BigorU [14]

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's Solve ~

$\qquad \sf \dashrightarrow \: 4 {x}^{2} + 20x + 25$

$\qquad \sf \dashrightarrow \: 4 {x}^{2} + 10x + 10x + 25$

$\qquad \sf \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)$

$\qquad \sf \dashrightarrow \: (2x + 5) (2x + 5)$

$\qquad \sf \dashrightarrow \: (2x + 5) {}^{2}$

$\sf{\qquad \sf \dashrightarrow \: 4x² + 20x + 25 }$

$\sf{\qquad \sf \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}$

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

$\sf{\qquad \sf \dashrightarrow \: (2x + 5)²}$

I hope it was helpful ~

3 0

2 years ago

PLEASE HELP

Ainat [17]

Answer: b

Step-by-step explanation:

8 0

3 years ago