The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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What answers well whats the question?
Y<-60
hope this helps and good luck;)
Answer:
I believe the answer is C :)
Step-by-step explanation:
Answer:
C and D
Step-by-step explanation:
1
The arc length is calculated as
arc = circumference of circle × fraction of circle
= 2πr × 
= 2π × 10 × 
= 
= 
cm → C
-----------------------------------------------------
2
The area (A) of a sector is calculated as
A = area of circle × fraction of circle
= πr² ×
= π × 10² × = 
= 
cm² → D
