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2 years ago

Find the length of the altitude a. I need help ASAP.

Mathematics

1 answer:

Mashutka [201]2 years ago

3 0

Answer:

Step-by-step explanation:

sin38=a/14

a=14(sin38)

a=8.61926

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The set of possible values of m is (5, 7, 9).

Vladimir [108]

The values of k are 4,5,6

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3 years ago

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Calculate the perimeter of this shape.<br> 12 cm<br> 18 cm

chubhunter [2.5K]

Answer:

Step-by-step explanation:

P = 2l + 2w

= 2(12) + 2(18)

= 24 + 36 = 60

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3 years ago

I am four times as old as my daughter. In 20 years time I shall be twice as old as her. How old are we now?

SashulF [63]

Answer:

If x is my daughter's age now, my age now is 4x. So now my daughter is 10 years old, and I'm 40 years old, and in 20 years she'll be 30 and I'll be 60, twice as hers.

Step-by-step explanation:

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3 years ago

Carla needs to purchase carpet for her living room what is the area of carla's living room.

e-lub [12.9K]

Answer:

92 ft squared

Step-by-step explanation:

6*7=42

5*10=50

42+50=92 ft squared

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3 years ago

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Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago