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3 years ago

5

Which two numbers should the answer to the missing side be between.

1 answer:

GREYUIT [131]3 years ago

6 0

the answer is between 11 and 12

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The function g(x)=|5x|-4 is a horizontal (blank) of the function f(x)=|x|-4

hodyreva [135]

Answer:

(

f

∘

g

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(

x

)

=

5

x

(

g

∘

f

)

(

x

)

=

5

x

+

16

5

hjvftvubgyhujkh

Step-by-step explanation:

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%7D%205%7D" id="TexFormula1" title="\frac{1}{\sqrt{x} 5}" alt="\fr

murzikaleks [220]

Answer:

$\frac{ \sqrt{5x} }{5x}$

Step-by-step explanation:

$\frac{1}{ \sqrt{x5} }$

$= \frac{1}{ \sqrt{5x} }$

$= \frac{1}{ \sqrt{5x} } \times \frac{ \sqrt{5x} }{ \sqrt{5x} }$

$= \frac{1 \sqrt{5x} }{ \sqrt{5x \sqrt{5x} } }$

$= \frac{\sqrt{5x} }{ \sqrt{5x \sqrt{5x} } }$

$= \frac{ \sqrt{5x} }{5x}$

8 0

3 years ago

» What is the product?<br> 0.9 x 100 =

Zepler [3.9K]

The product of this is 90

4 0

3 years ago

Read 2 more answers

Which is true about the diagram below?

SOVA2 [1]

Answer:

third option: "The sum of the areas of Square 1 and Square 2 will equal the area of Square 3"

Step-by-step explanation:

This is the derivation for the Pythagorean Theorem

6 0

3 years ago

Read 2 more answers

I dont understand this at all

Zigmanuir [339]

$\huge\text{Hey there!}$

$\huge\textbf{What are we solving for?}$

$\mathsf{56 = w(w + 10) }$

$\huge\textbf{How are we going to solve for the}\\\\\huge\textbf{equation?}$

$\mathsf{56 = w(w + 10)}$

$\mathsf{w(w + 10) = 56}$

$\mathsf{w(w) + w(10) = 56}$

$\mathsf{w(w) + 10(w) = 56}$

$\mathsf{w^2 + 10w = 56}$

$\huge\textbf{Subtract \boxed{\bf 56} to both sides:}$

$\mathsf{w^2 + 10w - 56 = 56 - 56}$

$\huge\textbf{Simplify it:}$

$\mathsf{w^2 + 10w - 56 = 0}$

$\huge\textbf{Factor the left side of the equation:}$

$\mathsf{(w - 4)(w + 14) = 0}$

$\mathsf{(w - 4)\times(w + 14) = 0}$

$\huge\textbf{Simplify it:}$

$\mathsf{w - 4 = 0\ or\ w + 14 = 0}$

$\mathsf{w = 4\ or \ w = -14}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\frak{\mathsf w = 4\ or \ \mathsf w = -14}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

6 0

2 years ago