All categories

2 years ago

Plz answer 100 points!!!!!

Mathematics

1 answer:

zlopas [31]2 years ago

7 0

Answer:

$3x + ( - 2 - 3) = 19 \\ 3x+(- 5) = 10 + 9 \\ (1 + 2)x + ( - 5) = 19$

all values stand for 3x+(-5)=19

3x-5=19=> 3x=24=> x=8.

Three step requires another step, so it is difficult than two step process.

no, their is no limit to the number of steps it take to solve an equation.

Every number can be described as a sum/difference of two or three numbers.

You might be interested in

A shop sells packs of black pens, packs of red pens and packs of green pens.

olchik [2.2K]

Answer:

85 pens

Step-by-step explanation:

The computation of the number of green pens sold is shown below;

As the number of black pens, red pens, and green pans is 3:5:6

And, the ratio of sold of black pens, red pens, and green pans is 7:3:4

So, the ratio of pens in a number of pens is

= 3 × 7 : 5 × 3 : 4 × 6

= 21: 15 : 24

= 7: 5 : 8

And, the total of 212 pens are sold

So, the number of green pens sold is

= 8 × 212 ÷ (7 + 5 + 8)

= 85 pens

4 0

3 years ago

a total of 695 tickets were sold for the school play. They were either adult or student tickets. There was 55 fewer students tic

FinnZ [79.3K]

Answer:

375 + 320

Step-by-step explanation:

375 adult

320 students

equals 395

4 0

2 years ago

Find the 52nd term of the following arithmetic sequence. 3, 9, 15, 21,

Alex Ar [27]

Answer:

309

Step-by-step explanation:

a = 3, d = 6, n 52

Nth term of an Arithmetic sequence is given as:

$t_n=a +(n-1)d \\ \therefore \: t_{52}=3 +(52-1) \times 6 \\ \therefore \: t_{52}=3 +51\times 6 \\ \therefore \: t_{52}=3 +306 \\ \huge \red{ \boxed{\therefore \: t_{52}=309 }}\\$

4 0

3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

State the slope, y intercept and a linear equation from the given graph. Please help

Luba_88 [7]

Answer:

below

Step-by-step explanation:

y = -2x/3 - 4

m = 2x/3

b= 4

y= -x +2

m= -1

b = +2

y= -x-2

m = -1

b =-2

6 0

2 years ago

Read 2 more answers