Help me solve this problem please

Mathematics

1 answer:

miss Akunina [59]3 years ago

7 0

Answer:

JL = 54

Step-by-step explanation:

JL = JK + KL

JK = KL

8x+11 =14x-1

12 = 6x

x = 2

substitute for x:

8(2)+11 + 14(2)-1 = JL

JL = 16+11+28-1

JL = 54

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Is (1, 2) a solution of the system?

PIT_PIT [208]

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3 years ago

My circumference is 20 cm what is my diameter and radius?

Musya8 [376]

Answer:

The diameter of the circle would be: 6.4 cm. rounded or 6.36619772 cm.

The radius of the circle would be: 3.2 cm. rounded or 3.18309886 cm.

Step-by-step explanation:

<h3>The diameter can be solved using: D = $\frac{C}{\pi }$ </h3>

So, the first step would be : D = $\frac{20}{\pi }$

Then : D = 20 ÷ $\pi$

Finally, the answer will be : 6.36619772 cm. or 6.4 cm.

<h3>The Radius can be Solved using: r = $\frac{c}{2\pi }$ </h3>

The first step would be : r = $\frac{20}{2\pi }$

Then : 20 ÷ 6.2831853071796 (2 $\pi$ )

Finally, the answer will be : 3.18309886 cm. or 3.2 cm.

7 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Solve for x.<br><br> 3x2 + 13x = 10

AlekseyPX

$3x^2+13x=10\ \ \ |-10\\\\3x^2+13x-10=0\\\\3x^2+15x-2x-10=0\\\\3x(x+5)-2(x+5)=0\\\\(x+5)(3x-2)=0\iff x+5=0\ \vee\ 3x-2=0\\\\x+5=0\ \ \ \ |-5\\\boxed{x=-5}\\\\3x-2=0\ \ \ \ |+2\\3x=2\ \ \ \ |:3\\\boxed{x=\dfrac{2}{3}}\\\\Answer:\ x=-5\ or\ x=\dfrac{2}{3}$