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den301095 [7]
3 years ago
13

Tim is selling tickets to a school sporting event to raise money for his club. He put some extra money in his box before he bega

n. As he sells tickets, he records the number of tickets he has sold and the total amount of money in the box. Some of his data is shown below:
Number of tickets sold Total money in box(dollars)

7 108.75
13 146.25
18 177.50

Assuming all the tickets are the same price, write an equation that represents the situation above. Explain how to use your equation to determine the amount of money originally in the box before any tickets were sold and the price of each ticket.
Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
The price of each ticket will be the slope found from the data.  

Slope=m=(y2-y1)/(x2-x1)=(177.5-146.25)/(18-13)

m=6.25  (so the cost of the tickets is $6.25)

Now we can use any data point to solve for b, or the y-intercept of the line:

y=6.25x+b, using (177.5, 18)

177.5=6.25(18)+b

b=$65.00d

So he started with $65.00
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A person borrows $10,000 and repays the loan at the rate of $2,400 per year. The lender charges interest of 10% per year. Assumi
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Answer:

a) M(t)=24000-14000e^{t/10}

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Step-by-step explanation:

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\frac{dM}{dt}=0.1M-2400

We can express this equation as:

\frac{dM}{dt}=0.1M-2400\\\\10\int \frac{dM}{M-24000} =\int dt\\\\10ln(M-24000)=t\\\\M-24000=Ce^{t/10}\\\\M=Ce^{t/10}+24000\\\\M(0)=Ce^{0/10}+24000=10000\\\\C+24000=10000\\\\C=-14000\\\\M(t)=24000-14000e^{t/10}

(b) We can calculate this as M(t)=0

M(t)=24000-14000e^{t/10}=0\\\\e^{t/10}=24000/14000=1.714\\\\t=10ln(1.714)=10* 0.5390=5.390

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