Solution:
iv) Given equation: 
Since we are given two variables, we need to split the original expression into two quadratic expressions as

Factoring x first:

= 
= 

Factoring y now:

= 
= ![-1[ y(y+1) + 1(y+1)]](https://tex.z-dn.net/?f=-1%5B%20y%28y%2B1%29%20%2B%201%28y%2B1%29%5D)
= ![-1 [(y+1)(y+1)]](https://tex.z-dn.net/?f=-1%20%5B%28y%2B1%29%28y%2B1%29%5D)
= 
Therefore, the original expression becomes

There is some information missing in the question, since we need to know what the position function is. The whole problem should look like this:
Consider an athlete running a 40-m dash. The position of the athlete is given by
where d is the position in meters and t is the time elapsed, measured in seconds.
Compute the average velocity of the runner over the intervals:
(a) [1.95, 2.05]
(b) [1.995, 2.005]
(c) [1.9995, 2.0005]
(d) [2, 2.00001]
Answer
(a) 6.00041667m/s
(b) 6.00000417 m/s
(c) 6.00000004 m/s
(d) 6.00001 m/s
The instantaneous velocity of the athlete at t=2s is 6m/s
Step by step Explanation:
In order to find the average velocity on the given intervals, we will need to use the averate velocity formula:
so let's take the first interval:
(a) [1.95, 2.05]
we get that:
so:
(b) [1.995, 2.005]
we get that:
so:
(c) [1.9995, 2.0005]
we get that:
so:
(d) [2, 2.00001]
we get that:
so:
Since the closer the interval is to 2 the more it approaches to 6m/s, then the instantaneous velocity of the athlete at t=2s is 6m/s
Answer:
no i dont want too
Step-by-step explanation:
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Answer:
None of the above
Step-by-step explanation:
F - 40y
G - 4y
H - 40y
J y+4
Answer:
The two values are 100 x 100 x 100 and 1 x 10 to the power of 3
Step-by-step explanation: