Answer:
a) Angle XBC = 55 because XY is parallel with BD
b) As given, XB = XC, so that triangle XBC is the equilateral triangle.
As XBC is equilateral triangle, angle XBC is equal to angle XCB
Angle XBC = 55° => Angle XCB = 55°
In a triangle, the total value of three corners are equal to 180°
So that: Angle XBC + Angle XCB + Angle BXC = 180°
=> 55° + 55° + Angle BXC = 180 °
=> Angle BXC = 70°
Answer:
To find critical points, take the first derivative and set it equal to zero:
f(x) = -2x^2 + 4x + 5
f'(x) = -4x + 4
-4x+4 = 0
-4x = -4
x = 1
Critical point at x = 1
Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.
You would multiply 50x16 being 16 ounces= 1 pound and than divide that by 10
point slope form of a line
y-y1 = m(x-x1)
y-4 = -3(x--5)
y-4 =-3(x+5)
to change to slope intercept form
dstribute
y-4 = -3x-15
add 4 to each side
y = -3x-15+4
y = -3x-11
Answer:
just do it Like Nikey
Step-by-step explanation:
lol
