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3 years ago

Find the area of a trapezoid with a base 1 of 13 cm, base 2 of 9 cm, and height of 11 cm.

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

The answer would be 16.5 cm^2

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Give a # that makes 10 - x < 5 true.

yaroslaw [1]

40 or literally any number greater than 10.

3 0

3 years ago

I need help pls. Algebra

andrew11 [14]

Answer:

<h3>The answer is option A</h3>

Step-by-step explanation:

f(x) = (x+1)³ + 4

To find f-¹(x) equate f(x) to y

That's

y = (x+1)³ + 4

Next interchange the terms x becomes y and y becomes x

That's

x = ( y+1)³ + 4

Make y the subject

(y+1)³ = x - 4

Find the cube root of both sides

That's

$y + 1 = \sqrt[3]{x - 4}$

Send 1 to the right side of the equation

That's

$y = \sqrt[3]{x - 4} - 1$

So we have the final answer as

$f ^{ - 1} (x) = \sqrt[3]{x - 4} - 1$

Hope this helps you

7 0

3 years ago

Read 2 more answers

Need the values IN FRACTIONS (no mixed numbers or decimals)

Liono4ka [1.6K]

$\left(-\frac{1}{2}\right)^1=-\frac{1}{2}\\
\left(-\frac{1}{2}\right)^2=\frac{1}{4}\\
\left(-\frac{1}{2}\right)^3=-\frac{1}{8}\\
\left(-\frac{1}{2}\right)^4=\frac{1}{16}\\
\left(-\frac{1}{2}\right)^5=-\frac{1}{32}\\$

6 0

3 years ago

Simplify. 7√50x^15y^21 Assume x and y are nonnegative.

sattari [20]

Given expression is $7 \sqrt{50x^{15}y^{21}}$ where x and y are non negative.

Now we have to simplify this to find the correct matching choice.

$7 \sqrt{50x^{15}y^{21}}$

$=7 \sqrt{25*2x^{15}y^{21}}$

$=7 \sqrt{25*2x^{14}*xy^{20}*y}$

$=7*5x^{7}y^{10} \sqrt{2*x*y}$

$=35x^{7}y^{10} \sqrt{2xy}$

Which best matches with choice D.

Hence final answer is $35x^{7}y^{10} \sqrt{2xy}$ .

7 0

3 years ago

Asa received scores of 72, 97, and 82 on her last three math tests. she needs a mean test score of 82 to qualify for the math te

lara [203]

First step is to find what should be the required total of sum of Score after fourth test, to identify how much more or less she need to score in his fourth test.

Since Mean = (Sum of Scores)/number of test

using above formula we determine what is the required sum of score.

82 = (Sum of Scores)/4

⇒ 82 × 4 = 328

So in four test she should have score total as 328

So Score require in fourth test = Required Score Total - (total score in 3 tests)

= 328 - ( 72 + 97 + 82 ) = 77

So she need score of 77 to be at mean of 82 after fourth test and get qualify for the team

6 0

4 years ago

Read 2 more answers