Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer: $42.4 dollars
Step-by-step explanation: PLZ PLZ PLZ MARK BRAINLIEST
Answer:
I think it's 9x/7
Step-by-step explanation:
Hope my answer has helped you.
So So sorry, I answered so late xd
The mean can be found by adding all the numbers then dividing it by the amount of numbers
The mean for team A is about 7.7
and the mean for team B is about 7.6
So they're A.) About the same
To find the range find the biggest number then subtract it by the smallest
Team A: 12,0 ; 12 - 0 = 12
12 is the range
Team B: 12,3 ; 12 - 3 = 9
The answer is B.) <span>much greater for conference a than for b</span>
Answer:
-15
Step-by-step explanation:
9-(9-1*3)
9-8*3
9-24
-15
