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Nata [24]
3 years ago
7

Seth has swimming practice three days each week. This week Seth swam a total of 114 laps. At this rate, how many laps did Seth s

wim on average each day?
Mathematics
2 answers:
Nataly [62]3 years ago
8 0
The answer is 38 laps per day
Bumek [7]3 years ago
5 0

Answer: 38 laps a day

Step-by-step explanation: So, he swam three days and he swam 114 laps in total. What you need to do is divide

how many laps he did in total/how many days he swam

114/3=38

Hope this helps, if you liked my answer please mark me brainliest, it really helps :)

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A system of equations is shown. y = 2x - 7 y = -x + 5 What is the solution to the system of equations? Please Show your work
elixir [45]
Are u sure u didnt write this wrong? maybe it’s x=2y-7? this doesn’t make sense :(
4 0
3 years ago
2.4z+1.2z-6.5=0.7 I don't get it
almond37 [142]
Basically that answer is incorrect. If you'd learn about combining, multiplying, dividing or subtracting like terms, this will be a simple problem. To be specific, like term is a number with a letter with it.

For example, 2.4z is a like term.

so you can only add like term, not any other normal number. When two terms have the same "letter", you will have to do what the sign said so in the problem....

2.4z + 1.2z - 6.5 = 0.7
3.6z - 6.5 = 0.7 (Add but leave the z alone because you are not multiplying)

The final answer is 3.6z - 6.5 because you cannot do anything else to that problem.

3.6z-6.5=0.7 is not true.
3 0
3 years ago
To mix mortar to lay bricks,you need 2.5Kg of cement,4kg of sand and 3 liters of water.Sand is sold in 10kg bags.How much cement
dedylja [7]

Answer:

6.25 kg cement, 7.5 L water

Step-by-step explanation:

2.5 kg cement / 4 kg sand = x kg cement / 10 kg sand

x = 6.25

3 L water / 4 kg sand = y L water / 10 kg sand

y = 7.5

6 0
3 years ago
Prove that the Greatest Integer Function f: R -> R given by f(x) = [x], is neither one-once nor onto, where [x] denotes the g
Karo-lina-s [1.5K]
F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one

Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7

So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.

The answer was quite complicated but I hope it will help you.
8 0
4 years ago
3/5 + 1/2 in simplest form
nordsb [41]
Make them common denominator
3/5 = 6/10
1/2 = 5/10
6/10 + 5/10 = 11/10 = 1 1/10
4 0
3 years ago
Read 2 more answers
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