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lbvjy [14]
3 years ago
11

A scale drawing of an NFL goalpost uses a scale of 2 inches=5 feet. If the actual width of the goal post is 18 1/2 feet, what is

the width of the goal post on the drawing?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

sorry friend I need some points and ya posted 3 of em

Step-by-step explanation:

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What is the domain and range of the relation shown in the table?
Alborosie

Answer:

Domain {-1, 0, 4}  

Range {2, 3, 4, 7}

Step-by-step explanation:

domain is the x's with each listed once

range is the y's with each listed once

8 0
4 years ago
K & P Toy Store is having a storewide sale. Remote control cars are on sale for 70% of their regular price, and sports equip
lord [1]

Answer:

Answer and steps in picture.

5 0
3 years ago
Find the area of each parallelogram. What is the relationship between the areas?
castortr0y [4]

Answer:

Area of parallelogram is given by:

A = bh

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12 units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12 units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = QR \cdot PT

⇒Area of parallelogram TQRS = 12 \cdot 12 = 144 unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3 units

P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3 units

Then;

Area of parallelogram T'Q'R'S' = Q'R' \cdot P'T'

Area of parallelogram T'Q'R'S' = 9 \cdot 9= 81 unit square.

Now, we have to find the relationship between the areas.

\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}



7 0
3 years ago
The slope of the line passing through the points (k, 1) and (5, -11) is perpendicular to the line 4x + 3y = -21. What is the val
pishuonlain [190]

Answer:

21

Step-by-step explanation:

all the details are in the attached picture.

7 0
3 years ago
If 7 x 88 = 616, then A) 7 ÷ 616 = 88 B) 88 ÷ 616 = 7 C) 88 ÷ 7 = 616 D) 616 ÷ 88 = 7
slavikrds [6]

If 7 x 88 = 616, then 616 / 88 = 7.

7 / 616 = 0.011

88 / 616 = 0.14

88 / 7 = 12.57

616 / 88 = 7

Hope this Helps!!

5 0
3 years ago
Read 2 more answers
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