Ask question

Ask question

All categories

2 years ago

15

If someone mixes 36 liters of orange juice and 45 liters of soda water, how many batches would they make?

1 answer:

sashaice [31]2 years ago

8 0

Answer:

9 batches

Step-by-step explanation:

(Found the full problem online)

1 batch : 4 liters of orange juice and 5 liters of soda water

How do we get from 4 and 5 to 36 and 45? For both we multiply by 9.

4 * 9 = 36

5 * 9 = 45

Therefore, they would be able to make 9 batches.

Hope this helps, please mark brainliest if possible :)

You might be interested in

20x^2=256+128x. Solve by Factoring.

givi [52]

Hey there,
20x ^ 2 = 256 + 128x
400x = 256 + 128x
400x - 128x = 256
272x = 256
x = 256 / 272
= <span>0.94117647058
=0.9

Hope this helps :))

<em>~Top♥</em>
</span>

8 0

3 years ago

An airplane flies 3,080 km from Houston to New York at a speed of 770 km/h. How long did it take the plane to travel that distan

garik1379 [7]

Answer:

time = distance/speed

3080/770 = 4

So it took 4 hours.

Step-by-step explanation:

5 0

3 years ago

Select all the sets of numbers that are possible values for x in the inequality, x>- 2.

lana66690 [7]

Answer:

{-1, 0,5}

Step-by-step explanation:

3 0

3 years ago

LII<br> Animals Seen in the Forest<br> 20<br> Number of Animals<br> Deer<br> Birds Bears Squirrels

Darya [45]

What’s the question?

4 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago