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Alja [10]
2 years ago
15

If someone mixes 36 liters of orange juice and 45 liters of soda water, how many batches would they make?

Mathematics
1 answer:
sashaice [31]2 years ago
8 0

Answer:

9 batches

Step-by-step explanation:

(Found the full problem online)

1 batch : 4 liters of orange juice and 5 liters of soda water

How do we get from 4 and 5 to 36 and 45? For both we multiply by 9.

4 * 9 = 36

5 * 9 = 45

Therefore, they would be able to make 9 batches.

Hope this helps, please mark brainliest if possible :)

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Translate the sentence into an inequality.
Luda [366]

Answer:

5 + c > -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Inequalities

Step-by-step explanation:

<u>Step 1: Define</u>

Sum of 5 and c is greater than -22

↓ <em>Identify</em>

Sum = addition

  • 5 + c

Is greater than = inequality

  • >

Add them all together:

5 + c > -22

8 0
3 years ago
Determine the center and radius of the following circle equation: x² + y2 - 6x + 16y + 48 = 0​
motikmotik

Answer:

center (3,-8)

radius=5

4 0
3 years ago
It’s two parts help me
ehidna [41]

Answer:

40 degree acute

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve it! Hurry<br> Will mark as brainliest<br> IF U TRY TO get the points free i would report u
Afina-wow [57]

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

verified

B.

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EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
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