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2 years ago

The coefficient of x in the expansion of (x + 3)(x - 1) is

Mathematics

1 answer:

jarptica [38.1K]2 years ago

8 0

waifuhaditallte

Step-by-step explanation:

You might be interested in

What is the answer to 7-7(1x-7)>-4+5x

earnstyle [38]

7 - 7(x - 7) > -4 + 5x
7 - 7x + 49 > -4 + 5x
56 - 7x > -4 + 5x
-7x - 5x > -4 - 56
-12x > -60
x < -60/-12
x < 5

6 0

2 years ago

Students and adults purchased tickets for a recent school play. All tickets were sold at

algol [13]

Answer:

120 student and 80 adult tickets

Step-by-step explanation:

8x + 10y = 1760

x + y = 200

8 0

3 years ago

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe

timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

$EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5$

So,

$EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1$

And

$GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)$

Now

$FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\ ..... (2)$

Solving (1) and (2)

b = - 2 ,

$a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6$

3 0

3 years ago

An investment firm invested in two companies last year. They invested $11,000

NeX [460]

(a) total profit
=11000*24%+14000*15%
=2640+2100
=$4740

(b) percent profit
=4740/(11000+14000)
= 0.1895
=18.96%

7 0

2 years ago

Solve please 3y^4t^-2/11y^-4

FrozenT [24]

Answer:

$\dfrac{3y^8}{11t^2}$

Step-by-step explanation:

$\dfrac{3y^4t^{-2}}{11y^{-4}} =$

$= \dfrac{3y^{4 - (-4)}}{11t^2}$

$= \dfrac{3y^8}{11t^2}$

8 0

2 years ago