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Slav-nsk [51]
3 years ago
14

A sociologist recently conducted a survey of senior citizens who have net worths too high to qualify for Medicaid but have no pr

ivate health insurance. The ages of the 25 uninsured senior citizens were as follows:
69 74 75 62 70 93 64 69 61 88 67 77 87 90 66 91 77 63 82 82 71 74 76 65 83


(a) Find the standard devation of the observations.


A. 74


B. 75.04


C. 94.95


D. 9.74


(b) Find the median of the observations. ト


A. 77


B. 74


C. 67.2


D. 83
Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

a) s= 9.74

D. 9.74

b) Median= 74

B. 74

Step-by-step explanation:

Part a

We have the following dataset given:

69 74 75 62 70 93 64 69 61 88 67 77 87 90 66 91 77 63 82 82 71 74 76 65 83

We can begin calculating the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 75.04

Now we can calculate the sample deviation with the following formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}

And after replace we got:

s= 9.74

Part b

For this case we need to sort the value on increasing way:

[1] 61 62 63 64 65 66 67 69 69 70 71 74 74 75 76 77 77 82 82 83 87 88 90 91 93

And the median would be the value in the position 13 and we got:

Median= 74

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Fifty draws are made at random with replacement from the box [ 0 0 1 1 1]. There are 33 ticket 1’s among the draws. The expected
Aleks04 [339]

Answer:

- The Expected value for the sum is 30.

- The Observed sum of 50 draws is 33.

- The Chance Error on the 50 draws is 3.

- The Standard Error on 50 draws is 2.191.

Step-by-step explanation:

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Using probability to predict the expected outcome.

On one draw, the probability of drawing a 0 is (2/5).

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Probability mass function would look like

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So, expected value on one draw would be

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Standard error on one draw = √[Σ(xᵢ - μ)²/N]

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Σ(xᵢ - μ)² = (0 - 0.60)² + (0 - 0.60)² + (1 - 0.6)² + (1 - 0.6)² + (1 - 0.6)² = 1.20

SE = √(1.2/5) = 0.490

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E(50X) = 50E(X) = 50 × 0.60 = 30.

For 50 draws, standard error = √50 × 0.490 = 2.191

The expected value for the sum = 30

The observed valued for the sum = (33×1) + (17×0) = 33

Chance Error = (Observed Outcome) - (Expected Outcome) = 33 - 30 = 3

Standard error gives an idea of how large the chance error would be.

Standard error on 50 draws = 2.191

Hope this Helps!!!

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