All categories

3 years ago

A bus covers a distance of 2.45 km in 2 min. What is the speed of bus?

Mathematics

1 answer:

Vladimir [108]3 years ago

7 0

Answer:

The speed of the bus is 74.242 kilometers per hour.

Step-by-step explanation:

Let suppose that bus runs at constant speed and that speed is measured in kilometers per hour. Then, the speed of the bus ( $v$ ), in kiometers per hour, is determined by following kinematic expression:

$v = \frac{s}{t}$ (1)

Where:

$s$ - Travelled distance, in kilometers.

$t$ - Time, in hours.

If we know that $s = 2.45\,km$ and $t = 0.033\,h$ , then the speed of the bus is:

$v = \frac{s}{t}$

$v = 74.242\,\frac{km}{h}$

The speed of the bus is 74.242 kilometers per hour.

You might be interested in

PLZ HELP ME BY THE END OF THE DAY

nlexa [21]

$3x^{2} +1=28$

Step 1 : subtract 1 from both sides

$3x^{2} =27$

Step 2 : Divide both sides by 3

$\frac{\frac{3x^{2} }{3} }{\frac{27}{3} }$

$x^{2} = 9$

Step 3 : Find the square root of 9

$\sqrt{9} = 3$

x= (-3,3)

remember negative × negative = positive

6 0

4 years ago

Help picture is shown!!!!

daser333 [38]

D,

Symmetry is when you split the shape, but they look the same.

6 0

4 years ago

Read 2 more answers

A soccer ball is kicked in the air and follow the path h(x)=2x2+1x+6, where x is the time in seconds and h is the height of the

denis-greek [22]

Answer:

You can either factor or use quadratic formula to find where h(x)=0

Step-by-step explanation:

Remember that the ball is on the ground when h(x)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.

4 0

3 years ago

Can someone pls help for brainlest

zvonat [6]

Answer:

area of the larger figure=32 yd×37 yd

=1184 yd²

area of the smaller figure=21 yd ×26 yd

=546 yd²

area of the shaded region=1184 yd² -546 yd²

<em>=638 yd²</em>

3 0

3 years ago

For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form

jek_recluse [69]

Answer:

$\displaystyle \cos(A + B) =\frac{969}{1769}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}$

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

$o=\sqrt{29^2-20^2}=21$

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

$h=\sqrt{11^2+60^2}=61$

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

$\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B$

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

$\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)$

Simplify:

$\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}$

3 0

3 years ago

A bus covers a distance of 2.45 km in 2 min. What is the speed of bus?​

A bus covers a distance of 2.45 km in 2 min. What is the speed of bus?