Answer:
See below
Step-by-step explanation:
![\sqrt[3]{49} = 3.65930571002 \approx3.66 \\ \\ so \: \sqrt[3]{49} should \: lie \: at \: 3.6 \: which \: \\ fall \: between \: 3 \: and \: 4.](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B49%7D%20%20%3D%203.65930571002%20%5Capprox3.66%20%5C%5C%20%20%5C%5C%20so%20%5C%3A%20%20%5Csqrt%5B3%5D%7B49%7D%20should%20%5C%3A%20lie%20%5C%3A%20at%20%5C%3A%203.6%20%5C%3A%20which%20%5C%3A%20%20%5C%5C%20fall%20%5C%3A%20between%20%5C%3A%203%20%5C%3A%20and%20%5C%3A%204.)
Actually Lin did a mistake, she obtained square root and not cube root.
Answer:

Step-by-step explanation:

hope this helps
brainliest appreciated
good luck! have a nice day!
In order to calculate that, we need to divide it by 1/5 as follows:
60/100 / 1/5
We can re-write it as: 60/100 * 5 = 6/10 * 5 = 30/10 = 3
So, there are "3" 1/5ths in 60/100
Hope this helps!
36 divided by 4 = 9
so then you take 3 times 9 which is 27 so the answer is
g=27
<u>Answer:</u>
$50 and $115
<u>Step-by-step explanation:</u>
We know that,
the sum of the two rates = $165 per hour
Let x and (165 - x) represent the $/hour of the 15hr and 5hr mechanics respectively.
Then combining their charges together to get:

Solving for x to get:



So the rate charged per hour by one mechanic is $50 and for the other mechanic =
$115.