Answer: y = -6x + 2
m = y_2 - y_1
/ x_2 - x_1
-10 - 8
/ 2 - (-1)
= -18/3 = -6
m (slope) = -6
y = mx + b
y = -6x +b
Find b using (-1,8)
y = -6x +b
8 = -6(-1) + b
8 = 6 + b
-6 -6
2 = b
Final answer: y = -6x + 2
To check using one of the points: (-1,8) or (2,-10)
y = -6x + 2
-10 = -6(2) + 2
-10 = -12 + 2
-10 = -10
This is a true statement.
Rate of change is also knkown as slope which is found by

=slope if you know 2 points/ordered pairs
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b
so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive
next
y=-4x
-4 =slope=negative
x increases while y decreases
negative
x increases while y decreases
negative
so
Positive
Negative
Negative
Negative
A. 6x-3y=12
sloope=-6/-3=2
B. y=5x+b
slope=5
C. (8-2)/(3-1)=6/2=3
sloope=3
D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4
5 is greates
B is the answer
A. (6-3)/(4-3)=3/1=3
slope=3
B. y=4+6x
slope=6
C.12x+6y=18
slope=-12/6=-2
D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5
greatest is 6
B is answer
the starting value I would guess si when x=1 what is the greats y value
look at each
first one
A. x=1 and =-3
B.y=3x-8
y=3(1)-8
y=3-8
y=-5
C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2
D. at 1 unit to right it is 1 nit up so y=1
greatest is 2 or C
so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon
for honey, just read off the graph
for when x=1
y=504
so calores of sugar=576
calories in honey=504
ANSWERS
Postive
Negative
Negative
Negative
B
B
C
sugar=576
honey=504
Answer with explanation:
The equation which we have to solve by Newton-Raphson Method is,
f(x)=log (3 x) +5 x²

Initial Guess =0.5
Formula to find Iteration by Newton-Raphson method




So, root of the equation =0.205 (Approx)
Approximate relative error

Approximate relative error in terms of Percentage
=0.41 × 100
= 41 %
So with the 10% discount, thats 45$, adding tax, that's <span>$47.70.</span>