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Helen [10]
4 years ago
13

Julio is paid 1.4 times his normal hourly rate for each hour he works over 30 hours in a week. Last week he worked 37 hours and

earned $569.14. Enter and solve an equation to find Julio's normal hourly rate, r.
Mathematics
1 answer:
deff fn [24]4 years ago
5 0
So I think u have to divide on this one
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Which of the following played a part in the development of Hebrew religious ideas?
erastovalidia [21]
A.
The Ten Commandments became a part of Hebrew culture and religion long before the Babylonian captivity.
6 0
3 years ago
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Plz answer BRAINLIEST Choose the statement that is true of both triangles.
saw5 [17]

Answer:

b

Step-by-step explanation:

gjhghjghj

8 0
3 years ago
Henry is looking for the best deal on a tablet that regularly costs $829. Help him compare the price of the tablet at a stre
Maslowich

Answer:

$165.8 ;

$223.83 ;

Henry would pay less for the tablet on the website.

Step-by-step explanation:

Given :

Regular price = $829

On website :

80% discount off the regular price :

(100 - 80)% * regular price

20% * 829

0.2 * $829 = $165.8

At store :

70% off regular price :

(100 - 70)% * 829

0.3 * 829

= $248.7

10% off sale price :

(100 - 10)% * $248.7

0.9 * 248.7

= $223.83

Henry would pay less for the tablet on the website.

5 0
3 years ago
. Let f(x) = x2 and g(x) = x − 3. Evaluate (g ∘ f)(−2). 1 7 20 −20
lesya692 [45]

For this case we have the following functions:

f (x) = x ^ 2\\g (x) = x-3

We must find(g_ {0} f) (x)

By definition we have to:

(g_ {0} f) (x) = g (f (x))

So:

g (f (x)) = (x ^ 2) -3 = x ^ 2-3

We must evaluate the composite function for x = -2

g (f (-2)) = (- 2) ^ 2-3 = 4-3 = 1

ANswer:

g (f (-2)) = 1

4 0
4 years ago
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How do you get this to its Standard Form?<br>And is it linear?
Alchen [17]

let's bear in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.


\bf \cfrac{x}{2}=\cfrac{y+3}{6}\implies\stackrel{\textit{multiplying by }\stackrel{LCD}{6}}{6\left( \cfrac{x}{2} \right)=6\left( \cfrac{y+3}{6} \right)}\implies 3x=y+3\implies \stackrel{\textit{standard form}}{3x-y=3}

4 0
4 years ago
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