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Hoochie [10]
3 years ago
6

What is the initial value of the function represented by this table?

Mathematics
2 answers:
max2010maxim [7]3 years ago
5 0

Answer: 3

Step-by-step explanation: initial value would be (when it’s at zero) and when the x value is at zero the y value is at three

Julli [10]3 years ago
4 0

Answer:

3

Step-by-step explanation:

Initial value represents the value of the function when the input (which here is x) is zero.  Looking at the table, we see that if x = 0, y = f(0) = 3.

The initial value of this function is 3.

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i honesty dont know if so i would help

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Marjorie bought a new car with some miles already clocked on it. She kept track of the miles she put on her new car each day, as
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the answer is 150

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3 years ago
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4/r=5/7solve for r. Help pls
antiseptic1488 [7]
Hello!

You first cross multiply

4 * 7 = 28

5 * r = 5 * r

r * 5 = 28

Divide both sides by 5

r = 28/5 = 5.6

The answer is 28/5 or 5.6

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4 0
3 years ago
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Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

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3 years ago
14. Determine if the statement is true or false.
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It depends if x is positive or negative and the same as in y
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