(—225) = [(—40)

At a party, the amount of people who ate meatballs was 9 less than 3/5 of the total number of people. The number of people who a

Luda [366]

Answer:

there were a total of 55 people at the party.

Step-by-step explanation:

In order to create the equation representing this scenario we first need to represent each step in a formula. Since the total number of people is represented by x we can multiply 3/5 by x and subtract 9 from that. This would then be equal to 24 like so...

3/5x - 9 = 24

Now that we have the formula we can perform opposite operations to isolate x and solve for it.

3/5x - 9 = 24 ... add 9 on both sides

3/5x = 33 ... divide both sides by 3/5

x = 55

Finally, we can see that there were a total of 55 people at the party.

3 0

3 years ago

-3(y+6)-4(y+3) simplify

Paha777 [63]

Answer:

-7y - 30

Step-by-step explanation:

-3y - 18 - 4y - 12

= -7y - 30

5 0

4 years ago

Read 2 more answers

Find all the zeros of the equation. -x^3-3x^2=6x+4

k0ka [10]

Answer:

The zeros of given expression $-x^3-3x^2=6x+4$ is -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

Step-by-step explanation:

Given expresssion is $-x^3-3x^2=6x+4$

To find zeros of given expression we have to equate the expression to zero.

ie., $-x^3-3^2-6x-4=0$

$-(x^3+3x^2+6x+4)=0$

$x^3+3x^2+6x+4=0$

By using synthetic division

-1 | 1 3 6 4

| 0 -1 -2 -4

|________________

1 2 4 0

Therefore (x+1) is a zero

Now the quadratic equation is $x^2+2x+4=0$

For quadratic equation $ax^2+bx+c=0$ we have

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a=1 ,b=2 and c=4 now substitute the values

$x=\frac{-2\pm \sqrt{2^2-4(1)(4)}}{2(1)}$

$x=\frac{-2\pm \sqrt{4-16}}{2}$

$x=\frac{-2\pm \sqrt{-12}}{2}$

$x=\frac{-2\pm \sqrt{12i^2}}{2}$ where $i^2=-1$

$x=\frac{-2\pm i \sqrt{4\times 3}}{2}$

$x=\frac{-2\pm i \sqrt{4}\sqrt{3}}{2}$

$x=\frac{-2\pm 2i\sqrt{3}}{2}$

$x=2\times\frac{(-1\pm i\sqrt{3})}{2}$

$x=-1\pm i\sqrt{3}$

Therefore $x=-1+i\sqrt{3}$ and $x=-1-i\sqrt{3}$

Therefore the zeros are -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

4 0

4 years ago

There are 45 questions on allison's English test. The multiple choice questions are worth 2 points each, and the short answers a

Vladimir [108]

You can solve this problem by creating a system of equations and solving by substitution. This allows you to solve for one of the unknown values (in this case, the number of short answer and number of multiple choice) and you can then solve for both, if you would like.

The two variables in your equations standing in for these missing values represent the number of short answer (s) and the number of multiple choice questions (m).

First create an equation for the number of total questions on the test. The total number of multiple choice and short answer questions is 45:
m + s = 45
Then create an equation with these variables representing the number of points on the test. The point values for each question will be the variable coefficients (numbers that the variables are multiplied by in this problem).
2m + 5s = 120

Now you can take the first equation - since it is simpler, the variables don't have coefficients so it only requires subtraction to get one variable by itself - solve for one of the variables, and substitute the result into the second equation in place of that variable. You will then be able to solve for that variable!

First, solve for m in the first equation by moving the m to one side of the equals sign by itself. It then becomes 45 - s = m

Now put (45-s) into the second equation in place of m.

120 = 2(45-s) + 5s

Distribute the 2(45-s)

120 = 90 - 2s + 5s

Add the "s" expressions together. Subtract 90 from both sides.

30 = 3s

Divide by 3 and find that s = 10

There are 10 short answer questions on the test.

7 0

3 years ago

(2x - 4) – 2 = 1 - 2(x – 3)<br> I need help with this one may someone help me??

AnnyKZ [126]

Answer:

$\boxed {x = \frac{13}{4}}$