Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Given:
Vertices of JKLM are J(−3,−2), K(−5,−5), L(1,−5), and M(3,−2).
To find:
The perimeter P of a parallelogram JKLM.
Solution:
Distance formula:
Using distance formula, we get
Similarly,
Now, perimeter P of ▱JKLM is
Therefore, the perimeter P of ▱JKLM is 19.2 units.
Answer:
Algebra tiles make solving equations, merging like words, or factoring polynomials a visual operation, similar to students using counters to make sense of addition in elementary school, or students using number lines to make sense of integers.
Step-by-step explanation:
i hope this helped
