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Lynna [10]
3 years ago
11

Angela and you are painting a room. Angela has 2 1/2 gallons of blue paint and Ryou has half as much white paint. It will take 2

3/4 quarts to cover each wall. If each wall is painted only one color, how many walls will be blue and how many will be white? How much paint will be left over?
Mathematics
1 answer:
GREYUIT [131]3 years ago
6 0
Conversion from gallons to quarts

1 gallon = 4 quarts

Now,

Angela has 2 \frac{1}{2} gallons = 2\frac{1}{2} *4 = 10 quarts of blue paint

Ryou has 1/2 of what Angela has = 1/2*10 = 5 quarts of white paint.

Each wall requires 2 \frac{3}{4} of paint.
After coloring;
Blue colored walls = (10)/(2 \frac{3}{4}) = 3 walls with 7/11 quarts of paint remaining.
White colored walls = (5)/(2 \frac{3}{4}) = 1 wall with 9/11 quarts of paint remaining
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Answer:

2x * 2x * 2x = 8x³

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Katena32 [7]
1. - Since a cube is all the same lengths on all sides you would want to find the area of one of the sides. You would do this by multiplying 3.8 by 3.8.
3.8*3.8=14.44
Since you have six faces on a cube you want to multiply this by 6.
14.44*6=86.64
So your answer for 1. is 86.64 in^2 of glass

3. Same thing as number one. Find the face of one side:
1 1/3*1 1/3 is about 1.7777
Multiply this by the six faces. 
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So your answer for 3. is about 10.666 (repeating) in^2

4. For this one, you want to follow the surface area formula for a cylinder. Which is - A=2πrh+2πr^2
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8 0
3 years ago
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
3 years ago
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