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butalik [34]
3 years ago
10

HELP if f(x)=25-x^2 and g(x)=x+5 what is (f/g)(x)?

Mathematics
1 answer:
SashulF [63]3 years ago
3 0
I hope this helps you

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What’s the area of 36 square meters perimeter of 30 meters what’s the width and length of those?
Anvisha [2.4K]
≠ means not equal to
L x w = 36
2L + 2w = 30

1. Find the multiples of 36

1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2. Figure out which set of numbers multiplied by 2 equals 30.

For 1 and 36:
2(1) + 2(36) = 2 + 72 = 74 ≠ 30

For 2 and 18:
2(2) + 2(18) = 4 + 32 = 36 <span>≠ 30

For 3 and 12:
2(3) + 2(12) =  6 + 24 = 30

So your answer is 3 and 12</span>
3 0
3 years ago
NEED HELP ASAP! WILL MARK BRAINlIEST!
Sav [38]

Answer:

6 ≤ x ≤ 12

Step-by-step explanation:

Instead of solving the area as 1.5*4x, you would do 6*x (multiply 1.5 by 4 and divide 4x by 4).

Then, you can just use division to find the answer.

36/6=6

72/6=12

And since 36≤A≤72, the area can be any number between 36 and 72, so x can be any number between 6 and 12.

3 0
3 years ago
Evaluate 3x+5(y+3) when x is 2 less than the quotient of y and 3, and y=12
myrzilka [38]

Answer:

81

Step-by-step explanation:

12/3 = 4

4 - 2 = 2

x = 2

using the order of operations, you would first have to do y + 3

y = 12

12 + 3 = 15

the equation simplified is 3 x 2 + 5 x 15

3 x 2 = 6

5 x 15 = 75

75 + 6 = 81

8 0
3 years ago
Helpppp pleaseeee ????
Agata [3.3K]

Answer:

LQ = 54

Median = 69

UQ = 94

Step-by-step explanation:

This list is already sorted for you, so you don't need to worry about that, otherwise you would need to sort the numbers in ascending order. To find the median, we do \frac{n+1}{2}, where n is the amount of numbers. This gives us 4, so the median is at position 4, so the median is 69. The lower quartile is simply \frac{n+1}{4}, so 2, so the lower quartile is 54. The upper quartile is \frac{n+1}{2} X 3, so 6, so the upper quartile is 94.

3 0
2 years ago
Find the volume to the nearest hunkeredth
Over [174]

Step-by-step explanation:

rjrurjrrmrjrjrnrbrbdu

5 0
2 years ago
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