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sashaice [31]
3 years ago
6

Five friends share 6 snacks equally. How many fruit snacks will each friend get?

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Irina18 [472]3 years ago
4 0
Each friend gets one and one fifth. (1 1/5)
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What is the x-intercept and y-intercept of the linear equation 3x-6y=2
sukhopar [10]

Answer:

The x-intercept is 2/3 and the y-intercept is -1/3

Step-by-step explanation:

In order to find this, we need to note that the x-intercept is the value of x, when y = 0. So we plug in y = 0 and see what the x value is.

3x - 6y = 2

3x - 6(0) = 2

3x = 2

x = 2/3

The y-intercept is the opposite. It is the y value when x = 0. So we do the same with the other term.

3x - 6y = 2

3(0) - 6y = 2

-6y = 2

y = -2/6

y = -1/3

8 0
3 years ago
Write a two-column <br> Give: <br><br> proof: x=45
AleksAgata [21]
Two lines that cross each other have each pair of angles the same.

2x+6=96 --> x=45
8 0
4 years ago
What are some values to make -2x&gt; 10 true ?<br> Please help ASAP!
steposvetlana [31]

Answer:

-6 -7 -8 -9 -10

Step-by-step explanation:

anything that keeps going from there dont do anything like -5 -4 -3 -2 -1 because it would be wrong

any negative number that keeps increasing after -6

7 0
3 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
Factor Quadratics
icang [17]

Answer:

Step-by-step explanation:

x^2 + 17x + 60

(x + 12)(x + 5)

8 0
3 years ago
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